Integral Of Arcsin - How To Discuss
Grace Evans
Integral Of Arcsin
What is the integral part of the arc at 2x?
. "Arcozin (2x) dx
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IU = arc sign (2x): do = 2 dex / ˆš (14x 2)
Dv = 1dx: v = x
. "Arxon (2x) dx = uv ˆÂ" video
= x arc (2 x)  x 2 x dex / ˆš (14x 2)
= Or 14x 2 = y
8x dx = dy
2x dx = dy / 4
= x arc (2 x) + 1 / 4 y dy / ˆšy
= x arxon (2x) + (1/4) / y / (1/2) + c
= x arxon (2x) + (1/2) + y + c
Change y = 14x 2
= x arxon (2x) + (1/2) ˆš (14x 2) + c
Integral Of Arcsin
Integral Of Arcsin
2x DX command
Use peer-to-peer integration to solve problems
Enter u = arc 2x du = 2 / sqrt (1 (2x) 2) in dx
dv = dx v = x
x arc 2x 2àˆà «â« x / sqrt (1 (2x) 2) in dx
x arc 2x 2àˆà «â« x / square (14x 2) in dx
Let's say W = 14x; 2DW = 8xDX
x Inner Arc 2x + 1/4 ˆÂ ˆÂ 1 / Square (W) DW
x Arc 2x + 1/2 in square (W) + C
x in arc 2x + 1/2 square (14x 2) + c
(1/2) * 1 / š (1 4x 2)
Integral Of Arcsin
Integral Of Arcsin
What is the essential part of the arc at 2x? ۔
ar "Arcosin (2x) dx
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let u = arc sine (2x): du = 2 dx / ˆš (14x 2)
dv = 1 dx: v = x
ar "arcsin (2x) dx = uv ˆÂ" vdu
= x arxon (2x) «« 2 x dx / ˆš (14x 2)
= Or 14x 2 = y.
8x dx = dy.
2x dx = dy / 4.
= x arcsen (2x) + 1 / 4 y dy / ˆšy
= x arcsin (2x) + (1/4) -y / (1/2) + c
= x arcsin (2x) + (1/2) -y + c.
Change y = 14x 2.
= x arcsin (2x) + (1/2) ˆš (14x 2) + c
2x dx bow.
Use peer-to-peer integration to solve problems.
Let u = arc be at 2x du = 2 / sqrt (1 (2x) 2) dx.
dv = dx v = x
x arc 2x 2Èà«x / sqrt (1 (2x) 2) in dx.
x arc 2x 2àˆÂ «x / sqrt (14x 2) in dx.
w = 14x 2 dw = 8x dx
x inner arc 2x + 1/4 «« 1 / sqrt (w) dw
x in arc 2x + 1/2 square (w) + c.
x Arc in 2x + 1/2 square (14x 2) + c.
Integral Of Arcsin
Integral Of Arcsin
What is the integral of the arc at 2x? 3
Arcosin (2x) DX
Merge after part
let u = arc sine (2x): du = 2 dx / ˆš (14x 2)
dv = 1 dx: v = x
Arxon (2x) dx = uv ˆ "vdu
= x arxon (2x)  «2 x dx / ˆš (14x 2)
= Or 14x 2 = y
8x dx = dy
2x dx = dy / 4
= x arxon (2x) + 1 / 4 «dy / ˆšy
= x arcsin (2x) + (1/4) ˆšy / (1/2) + c
= x arcsin (2x) + (1/2) ˆšy + c
Replace y = 14x 2
= x arcsin (2x) + (1/2) ˆš (14x 2) + c
2x dx bow
Use seamless integration to solve problems.
let u = arc in 2x du = 2 / sqrt (1 (2x) 2) dx
dv = dx v = x
x arc 2x 2Èà«x / sqrt (1 (2x) 2) in dx
x arc 2x 2 «x / sqrt (14x 2) in dx
Let w = 14x 2 dw = 8x dx
x inner arc 2x + 1/4 ˆÂ «1 / sqrt (w) dw
In x arc 2x + 1/2 square (w) + c
In x arc 2x + 1/2 square (14x 2) + c